Question

someone please help I am in a big big big hurry

Answer 1

Solve by factoring
m^2 + 8m +7=0

Answer 2

To factor this, we want to find some a and a such that \[(m+a)(m+b)=m^2+8m+7\]

Answer 3

*some a and some b, sorry!

Answer 4

When we expand that, we get \[(m+a)(m+b)=m^2+(a+b)m+a*b\]

Answer 5

A.) 8,7
B.) -7,1
C.) -7,-1
D.) 7,1

Answer 6

Since our final equation is \[m^2+8m+7\] we want a+b to equal 8, and a * b to equal 7. Can you find an a and b that work?

Answer 7

neither do i lol

Answer 8

im sorry @HarryPotter5777 I am having problems with this unit in school

Answer 9

The other way to solve them would be by plugging your options into your questions and checking whether L.H.S is equal to R.H.S.

Answer 10

im so confused

Answer 11

maybe this will help A.
m² + 8m + 7 = 0
Factor:
(m + 7) (m + 1) = 0
Set each set equal to 0
m + 7 = 0
m + 1 = 0
And solve:
m = -7
AND
m = -1

B.
c² = 8c
Subtract 8c from each side:
c² - 8c=0
Factor:
(c + 0) (c - 8)=0
Set each set equal to 0
c + 0 = 0
c - 8 = 0
And your answer is:
c = 0
AND
c = 8

Answer 12

yes thank you

Answer 13

u r welcome