Arctan(-radical3) answer in radians and decimal approximation

Question

anonymous · Answer

Try computing it this way. Let $x=\arctan(-\sqrt3)$, so then $\tan x=-\sqrt3$. Keep in mind the domain of one period of the tangent function, $-\dfrac{\pi}{2}$ to $\dfrac{\pi}{2}$.

What angle $x$ has a tangent of $-\sqrt3$?

anonymous · Answer

I know that there is difference between arctan and Arctan as well

anonymous · Answer

I wasn't aware of that. Care to elaborate?

anonymous · Answer

Well I'm not too sure but in my book it says " that the special use of the capital letter distinguishes inverse functions from corresponding inverse relations"

anonymous · Answer

$$\text{ArcTan}\left[-\sqrt{3}\right]=-\frac{\pi }{3}=-60{}^{\circ}=120{}^{\circ} $$

anonymous · Answer

ohh so its the same as arctan? ok :)

anonymous · Answer

because its funny that I would be asked to solve for arctan(-radical 3) and Arctan(-radical3) and the same for other numbers with sin and cos inverses just to get all the same answer twice

anonymous · Answer

can anyone confirm that they are both the same answers? because it is kinda odd

anonymous · Answer

arctan has to be typed "ArcTan" in Mathematica, a computer program, or the arctan function will not be invoked.

anonymous · Answer

ok