Question

How would you factor this.? Steps please. 2x^2=-24x-72

Answer 1

First you want to get all terms on the left side and set it equal to zero. Do you know how to do that?

Answer 2

\[2x^2 + 24x + 72 = -24x + 24x -72 + 72\]
Add 24x and 72 to both sides of the equation.

Answer 3

\[2x^2 + 24x + 72 = 0\]

Answer 4

\(\large {2x^2=-24x-72\implies 2x^2+24x+72=0
\\ \quad \\
\implies
\begin{array}{cccllll}
2(x^2&+12x&+36)=0\\
&\uparrow &\uparrow\quad \\
&6+6&6\cdot 6
\end{array}}\)

Answer 5

\[2(x^2 + 12x + 36) = 0\]

Answer 6

\[\frac{2}{2}(x^2 + 12x + 36) = \frac{0}{2}\]

Answer 7

Divide both sides by 2 to eliminate the 2 on the left side of the equation. From there you factor using the description @jdoe0001 gave three posts up.

Answer 8

You are looking for "what terms multiply to get 36 and add to get 12?"

Answer 9

Since all the terms of your polynomial are positive, the terms of your factored form will all be positive.

Answer 10

\[(x + \_\_)(x+\_\_) = 0\]

Answer 11

Fill in the blanks.