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Mathematics 19 Online
OpenStudy (anonymous):

Can someone help me with this statistic question, pleaseeee

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

standard error= \(\large \frac{\sigma}{\sqrt{n}} = \frac{10}{\sqrt{25}} = 2\)

ganeshie8 (ganeshie8):

for 95 % confidence interval you would take two standard errors

OpenStudy (anonymous):

for 95% CI the z* is 1.960

ganeshie8 (ganeshie8):

yes multiply your standard error wid that

OpenStudy (anonymous):

So i dont use [ME= z* (\mu \div \sigma)\]

OpenStudy (anonymous):

i got 3.92 is that my answer?

ganeshie8 (ganeshie8):

yes, you can use sample mean since you dont have the population mean availabble

OpenStudy (anonymous):

can you help me with another problem please

ganeshie8 (ganeshie8):

however thats not ur answer, wait a sec

OpenStudy (anonymous):

no it was correct. i got a check mark by it

OpenStudy (anonymous):

:)

ganeshie8 (ganeshie8):

3.92 is simply \(z*\frac{\sigma}{\sqrt{n}}\)

ganeshie8 (ganeshie8):

right ?

ganeshie8 (ganeshie8):

wow ! ok then we're good :) are you doing the coursera course ha ?

OpenStudy (anonymous):

OpenStudy (anonymous):

this is the next question, i keep getting the answer wrong.

OpenStudy (beccaboo333):

One question per post please :3 my hunnyboo xD can help you if you tag him in the next post.

OpenStudy (beccaboo333):

Just post that question after you close this :)

OpenStudy (beccaboo333):

OpenStudy rules~

ganeshie8 (ganeshie8):

yeah we can do that :)

ganeshie8 (ganeshie8):

but lemme take a look at the question.. .this does look similar to the previous one... again we're computing ME right ?

ganeshie8 (ganeshie8):

standard err = \(\large \frac{2.25}{\sqrt{10}}\) ME = \(1.96 \times \frac{2.25}{\sqrt{10}}\)

ganeshie8 (ganeshie8):

you got that ?

OpenStudy (anonymous):

now i see it. thank you so much

OpenStudy (anonymous):

would you use the same formula is you were supposed to find "n"

ganeshie8 (ganeshie8):

yes you can use...

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

\(\large 1 = z^{*}\frac{\sigma}{\sqrt{n}}\)

ganeshie8 (ganeshie8):

plug and chug given values

ganeshie8 (ganeshie8):

\(\large 1 = 1.96\frac{1}{\sqrt{n}}\) you can solve n

OpenStudy (anonymous):

I got it right but the 2nd question i asked was wrong

ganeshie8 (ganeshie8):

oh

OpenStudy (anonymous):

the ME= 1.96(2.25/sqrt 10)

ganeshie8 (ganeshie8):

that one it says wrong is it ?

OpenStudy (anonymous):

wait hold

OpenStudy (anonymous):

im so dumb, i rounded it wrong

ganeshie8 (ganeshie8):

ohhk... hope u can submit again :)

OpenStudy (anonymous):

OpenStudy (anonymous):

its still wrong

OpenStudy (anonymous):

i got the other one right

OpenStudy (anonymous):

Did I calculate it wrong?

ganeshie8 (ganeshie8):

yes, we calculated it wrong : try this : 0.690

OpenStudy (anonymous):

can you explain to me how did you got that number

ganeshie8 (ganeshie8):

we made a blunder, we plugged in mean incorrectly instead of standard deviation

OpenStudy (anonymous):

no its still wrong :(

OpenStudy (beccaboo333):

Nothing he says is wrong... EVER

ganeshie8 (ganeshie8):

ack... lol im also learning statistics i can be wrong :)

OpenStudy (beccaboo333):

SHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

ganeshie8 (ganeshie8):

last try : 0.703 http://www.wolframalpha.com/input/?i=2*1.11181%2Fsqrt%2810%29

OpenStudy (anonymous):

still wrong. dammnit.

ganeshie8 (ganeshie8):

one more : 0.689

ganeshie8 (ganeshie8):

http://www.wolframalpha.com/input/?i=1.96*1.112%2Fsqrt%2810%29 just messing wid the sigfigs from answer from q7

OpenStudy (anonymous):

nope still wrong.

OpenStudy (anonymous):

its fine, i just emailed my professor about this question

ganeshie8 (ganeshie8):

okie if psble do let me knw once u figure out the mystery lol

OpenStudy (anonymous):

lol i will :D thanks again though

ganeshie8 (ganeshie8):

np :)

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