Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

helpppppppp

OpenStudy (zolock):

with what

OpenStudy (anonymous):

\[\int\limits_{0}^{\pi/3}3secxtanx dx\]

OpenStudy (anonymous):

=

jimthompson5910 (jim_thompson5910):

hint: if y = sec(x), then dy/dx = sec(x)*tan(x)

OpenStudy (anonymous):

is sex the anti derrivative

OpenStudy (anonymous):

yup lol

OpenStudy (anonymous):

6

OpenStudy (anonymous):

no

jimthompson5910 (jim_thompson5910):

close, \[\Large \int 3\sec(x)\tan(x)dx = 3\sec(x)+C\]

jimthompson5910 (jim_thompson5910):

Now evaluate at the endpoints

OpenStudy (anonymous):

not sure how ?????

OpenStudy (anonymous):

frogot

OpenStudy (anonymous):

hello?

jimthompson5910 (jim_thompson5910):

this page gives an example of what I mean http://www.math.hmc.edu/calculus/tutorials/fundamental_thm/

OpenStudy (anonymous):

omg i thought the limit zero didn't matter. forgot about the sex lol dummmmmmmm

OpenStudy (anonymous):

sec^^^ lol

OpenStudy (anonymous):

3

jimthompson5910 (jim_thompson5910):

\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\sec(x) {\huge|}_{0}^{\pi/3}\] \[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = (3\sec(\pi/3)) - (3\sec(0))\] \[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = ???\]

OpenStudy (anonymous):

3

jimthompson5910 (jim_thompson5910):

\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\sec(x) {\huge|}_{0}^{\pi/3}\] \[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = (3\sec(\pi/3)) - (3\sec(0))\] \[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3*2 - 3*1\] \[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\] So you are correct.

OpenStudy (anonymous):

\[\int\limits_{?}^{?}x^5\sec^2(x^6)dx\]

OpenStudy (anonymous):

no limits

OpenStudy (anonymous):

do i use u substitution

jimthompson5910 (jim_thompson5910):

yes use u = x^6 so du/dx = 6x^5

jimthompson5910 (jim_thompson5910):

also keep in mind that if y = tan(x), then dy/dx = sec^2(x)

OpenStudy (anonymous):

right antiderrivative

OpenStudy (anonymous):

dx= du/6x^5

OpenStudy (anonymous):

what does 6x^5 cancel with ??

OpenStudy (anonymous):

the x^5????

OpenStudy (anonymous):

or no

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

cause you can do 1/6 *du/x^5

jimthompson5910 (jim_thompson5910):

du/dx = 6x^5 du = 6x^5*dx du/6 = x^5*dx

jimthompson5910 (jim_thompson5910):

so that means \[\Large \int x^5\sec^2(x^6)dx\] \[\Large \int \sec^2(x^6)*x^5dx\] \[\Large \int \sec^2(u)*du/6\] \[\Large \frac{1}{6}\int \sec^2(u)du\]

OpenStudy (anonymous):

yea thats what i got sorry i was brushing my teeth

OpenStudy (anonymous):

umm thats not one of my answers

OpenStudy (anonymous):

1/6tan(x^6)+6

OpenStudy (anonymous):

+c

OpenStudy (anonymous):

never mine it is sorry

jimthompson5910 (jim_thompson5910):

good, it's 1/6tan(x^6) + C

OpenStudy (anonymous):

the grapgh of f=f'x is shown. (looks like y=4). If F(0)=5, then F(5)=

OpenStudy (anonymous):

25???

OpenStudy (anonymous):

no sure

OpenStudy (anonymous):

|dw:1394069702221:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!