Mathematics
22 Online
OpenStudy (anonymous):
helpppppppp
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OpenStudy (zolock):
with what
OpenStudy (anonymous):
\[\int\limits_{0}^{\pi/3}3secxtanx dx\]
OpenStudy (anonymous):
=
jimthompson5910 (jim_thompson5910):
hint:
if y = sec(x), then dy/dx = sec(x)*tan(x)
OpenStudy (anonymous):
is sex the anti derrivative
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OpenStudy (anonymous):
yup lol
OpenStudy (anonymous):
6
OpenStudy (anonymous):
no
jimthompson5910 (jim_thompson5910):
close,
\[\Large \int 3\sec(x)\tan(x)dx = 3\sec(x)+C\]
jimthompson5910 (jim_thompson5910):
Now evaluate at the endpoints
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OpenStudy (anonymous):
not sure how ?????
OpenStudy (anonymous):
frogot
OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
omg i thought the limit zero didn't matter. forgot about the sex lol dummmmmmmm
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OpenStudy (anonymous):
sec^^^ lol
OpenStudy (anonymous):
3
jimthompson5910 (jim_thompson5910):
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\sec(x) {\huge|}_{0}^{\pi/3}\]
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = (3\sec(\pi/3)) - (3\sec(0))\]
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = ???\]
OpenStudy (anonymous):
3
jimthompson5910 (jim_thompson5910):
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\sec(x) {\huge|}_{0}^{\pi/3}\]
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = (3\sec(\pi/3)) - (3\sec(0))\]
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3*2 - 3*1\]
\[\Large \int_{0}^{\pi/3} 3\sec(x)\tan(x)dx = 3\]
So you are correct.
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OpenStudy (anonymous):
\[\int\limits_{?}^{?}x^5\sec^2(x^6)dx\]
OpenStudy (anonymous):
no limits
OpenStudy (anonymous):
do i use u substitution
jimthompson5910 (jim_thompson5910):
yes use u = x^6
so du/dx = 6x^5
jimthompson5910 (jim_thompson5910):
also keep in mind that if y = tan(x), then dy/dx = sec^2(x)
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OpenStudy (anonymous):
right antiderrivative
OpenStudy (anonymous):
dx= du/6x^5
OpenStudy (anonymous):
what does 6x^5 cancel with ??
OpenStudy (anonymous):
the x^5????
OpenStudy (anonymous):
or no
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jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
cause you can do 1/6 *du/x^5
jimthompson5910 (jim_thompson5910):
du/dx = 6x^5
du = 6x^5*dx
du/6 = x^5*dx
jimthompson5910 (jim_thompson5910):
so that means
\[\Large \int x^5\sec^2(x^6)dx\]
\[\Large \int \sec^2(x^6)*x^5dx\]
\[\Large \int \sec^2(u)*du/6\]
\[\Large \frac{1}{6}\int \sec^2(u)du\]
OpenStudy (anonymous):
yea thats what i got sorry i was brushing my teeth
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OpenStudy (anonymous):
umm thats not one of my answers
OpenStudy (anonymous):
1/6tan(x^6)+6
OpenStudy (anonymous):
+c
OpenStudy (anonymous):
never mine it is sorry
jimthompson5910 (jim_thompson5910):
good, it's 1/6tan(x^6) + C
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OpenStudy (anonymous):
the grapgh of f=f'x is shown. (looks like y=4). If F(0)=5, then F(5)=
OpenStudy (anonymous):
25???
OpenStudy (anonymous):
no sure
OpenStudy (anonymous):
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