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So i got sqrt root of -$423751.822100314 will be my standard deviation. how do i figure out my standard deviation, Se?
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which is 650.962227859892i. i in the end.. is it possible?
standard deviation must be always positive
can u show me how u got that ? :)
on no... i got negative...
@ganeshie8
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how ?
Ok i will show you
yes :)
\[Se =\sqrt{\frac{ \epsilon ei ^{2} }{ n-2 }}\]
Se=(\[Se=(\sqrt{\frac{ \epsilon yi-a \epsilon yi-b \epsilon xiyi }{ }}\]
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sorry below should be n-2
is that how u calculate standard error ? never seen this before :o
I plug numbers \[Se=\sqrt{314900-2328.76332288...(1750)-(14.263322.../(10-2)}\]
Yes, its economics.
not sure sorry :(
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you might want to provide more detail on what exactly you are doing.
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