Use the Law of Cosines to find the measure of angle S to the nearest degree. (Enter only the number.) I don't know if I'm doing something in the process wrong, but the answer I'm getting is too high. I'll attach the photo.
I know the formula is a^2=b^2+c^2-2bc cosA but I'm doing something wrong somewhere.
which angle do you want?
Angle S
ooh S ok you want the angle not the side, so start by solving \[ a^2=b^2+c^2-2bc\cos(A)\] for \(\cos(A)\)
you get \[\cos(A)=\frac{b^2+c^2-a^2}{2bc}\]
then since you want the angle, not the cosine of the angle, take the arccosine of whatever number you get
you good from there?
Thank you so much! The lesson never really went over HOW to solve so I never knew where to divide and all that. Now I understand. And I got S=39.7
i didn't do it, but i believe you it is a calculator exercise now yw btw \(\cos(A)=\frac{b^2+c^2-a^2}{2bc}\) is not hard to memorize, you don't really want to solve each time
Okay awesome! Again thanks so much!
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