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Mathematics 23 Online
OpenStudy (anonymous):

Use the Law of Cosines to find the measure of angle S to the nearest degree. (Enter only the number.) I don't know if I'm doing something in the process wrong, but the answer I'm getting is too high. I'll attach the photo.

OpenStudy (anonymous):

OpenStudy (anonymous):

I know the formula is a^2=b^2+c^2-2bc cosA but I'm doing something wrong somewhere.

OpenStudy (anonymous):

which angle do you want?

OpenStudy (anonymous):

Angle S

OpenStudy (anonymous):

ooh S ok you want the angle not the side, so start by solving \[ a^2=b^2+c^2-2bc\cos(A)\] for \(\cos(A)\)

OpenStudy (anonymous):

you get \[\cos(A)=\frac{b^2+c^2-a^2}{2bc}\]

OpenStudy (anonymous):

then since you want the angle, not the cosine of the angle, take the arccosine of whatever number you get

OpenStudy (anonymous):

you good from there?

OpenStudy (anonymous):

Thank you so much! The lesson never really went over HOW to solve so I never knew where to divide and all that. Now I understand. And I got S=39.7

OpenStudy (anonymous):

i didn't do it, but i believe you it is a calculator exercise now yw btw \(\cos(A)=\frac{b^2+c^2-a^2}{2bc}\) is not hard to memorize, you don't really want to solve each time

OpenStudy (anonymous):

Okay awesome! Again thanks so much!

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