Question

Please help. Will give medal and become a fan.

Answer 1

Look at the denominator. When will that equal 0 (remember, you can't divide by 0)?
\[x^2 + 3x +2\]
Factor that expression or use the quadratic equation
\[(x+2) (x+1)\]
Or quadratic equation:
\[\frac{-3 \pm \sqrt((-3)^2 - 4(1)(2)}{(2)(1)}\]
Solve to get x = -2, x = -1

Answer 2

Also, a hole occurs when both the numerator and denominator are equal to 0 (see http://www.sparknotes.com/math/algebra2/specialgraphs/section2.rhtml). Knowing that the denominator equal to 0 when x = -2 or -1, we see that the expression in the numerator cannot equal 0 when x = -2 or -1, so there are no holes.

Answer 3

@DisplayError thank you!