2. Let f be the function shown below, with domain the closed interval [0,6]. The graph of f is shown below, composed of two semicircles.
@agent0smith it's suppose to say "find the domain of..."
i want to know if we use the equation of a circle and divide it by 2, or the area of a circle and divide it by 2...
domain of f(t) is only from 0 to 6, so the domain of h(x) is the same, except it's from 0 to 2x-1, where 2x-1 must equal 6. Find x.
is t the independent variable on the graph? it's kinda fuzzy
Yeah idk why the question looks so terrible, crap all over the place.
well, then it's 0 <= 2x - 1 <= 6
so do main of h(x) is 1/2 <= x < 7/2
where does the integral come in place?
0 to x is 3
well, h(x) is defined by taking the integral of f(t), for t in [0,6]. There and since 2x-1 is in that interval, 0 <= 2x-1 <= 6
i mean x=3, so the domain is [0,3]
sorry about the pic, you guys.
when when x = 3, |dw:1394083520332:dw|
Join our real-time social learning platform and learn together with your friends!