Find an equation of the tangent line to the graph of the function at the point (1, 1).

y=x^(cosh(x))

y=????

Question

Find an equation of the tangent line to the graph of the function at the point (1, 1).

y=x^(cosh(x))

y=????

anonymous · Answer

first you have to get the slope of the tangent line
are you know how ?

anonymous · Answer

No

anonymous · Answer

Do I get it by getting the derivative?

anonymous · Answer

yes right 
get the derivative then use the point (1,1)

anonymous · Answer

$$x^(\cosh(x)-1) * (\cosh(x)+xlog(x)\sinh(x))$$

Do I just plug in the 1?

anonymous · Answer

are you sure about this result?

anonymous · Answer

I got it from WolframAlpha

anonymous · Answer

anyway 
a dont sure about this 
then plug in 
x=1
get y=?

anonymous · Answer

sorry 
get dy/dx  =?

anonymous · Answer

I'm not sure, I'm really lost

anonymous · Answer

i got 
$$\frac{ dy }{ dx }=x ^{coshx}\left[ lnx *sinhx +\frac{ 1 }{ x }coshx\right]$$

anonymous · Answer

then 
$$\frac{ dy }{ dx }=1^{\cosh1}\left[ \ln1 *\sinh1 +\frac{ \cosh1 }{ 1 } \right]$$

anonymous · Answer

calculate it

anonymous · Answer

I get cosh(1)

anonymous · Answer

good
then you have the data
slope =cosh1
point=(1,1)
can u use this data to create a line

anonymous · Answer

so the answer is cosh(x)? Because it's asking for a formula