Question

The function f(x)= x ln(x^a)-ax is defined for some positive constant a. For what x-value(s) does f'(x)=0?

Answer 1

can you get \[f \prime(x)\]

Answer 2

ln(x^a)+xaln(x)-a?

Answer 3

\[
\ln(x^a) = a\ln(x)
\]

Answer 4

no :(
\[y=xlnx ^{a}-ax\]
\[y=axlnx -ax\]
\[y \prime=a*lnx +ax*\frac{ 1 }{ x }-a\]

Answer 5

\[y \prime=alnx\]

Answer 6

now you have to
\[y \prime=0\]

Answer 7

\[alnx =0\]

Answer 8

Isn't it f'(1)=0

Answer 9

yes ln1=0