Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three, solve for f(g(x)) when x = 2

Question

campbell_st · Answer

well you need to subsitute 

$$\frac{x + 4}{3}$$

into f(x)

anonymous · Answer

i got 11, but i'm not sure i read your equations right.

campbell_st · Answer

then when you have substituted, and simplified

replace x with 2

then evaluate

anonymous · Answer

11 is a option i think ill give it a try. but thank you.

campbell_st · Answer

so 

$$f(\frac{x +4}{3}) = (\frac{x +4}{3})^2 + 2(\frac{x +4}{3}) + 3$$

campbell_st · Answer

so next replace x with 2 and evaluate

anonymous · Answer

Solution.
I Think this is the answer..
f(x) = x2 + 2x + 3
g(x) = x+4/3
Now we can get the f(g(x)) using this equation..
f(x+4/3) = (x+4/3)2 + 2(x+4/3) + 3
then x = 2
f(x+4/3) = (2+4/3)2 + 2(2+4/3) + 3
f(x+4/3) = 4 + 4 + 3
f(x+4/3) = 11
I think this is the answer..

whpalmer4 · Answer

@MaxLure while you got the right answer, it is very sloppy to write $\dfrac{x+4}{3}$ as $x+4/3$ as by the rules of operator precedence, they are not equivalent.  You should write $(x+4)/3 $ if you insist on forgoing the formatting tools the site provides.

anonymous · Answer

hahah sorry ..
i don't know how to use this tools over here..