A police investigator fires a 30 g bullet with a velocity of 360 m/s into a lead paperweight placed against a concrete wall. Because of a constant resistance force, the bullet penetrates 5.0 cm into the paperweight before coming to a stop. Calculate the initial momentum of the bullet in the paperweight.

Question

anonymous · Answer

@Mashy

anonymous · Answer

Initial momentum.. before the bullet gets embedded right?

anonymous · Answer

Yeah *before the collision sorry

anonymous · Answer

Nevermind just got it! Could you help with part b, the acceleration of the bullet in the paperweight.

anonymous · Answer

You know the initial velocity, the final velocity, and the displacement.. can you calculate time and acceleration?

anonymous · Answer

Right, I used the equation $$v _{2}^{2}=v _{1}^{2}+2a \Delta d$$ and got -1.3 x 10^-6 but the answer is -1.3 x 10^-7 am I doing something wrong?

anonymous · Answer

woops those exponents aren't negative, I meant -1.3 x 10^6 and  -1.3 x 10^7

anonymous · Answer

NO you are right.. its 1.3 X 10^6 m/s^2