in a shot out event a 2kg of shot is launched from a height of 1.50m, with an initial velocity of 8m/s at an angle of 60 degrees to horizontal

Question

rane · Answer

what is the maximum height from the ground that is reached by the shot ?

anonymous · Answer

by using the vertical component of velocity you can calculate h
$$v^2 =u^2 -2gh$$
at maximum height (h) v=0 ang u= 8 sin 60 
calculate h and add 1.5 you will get your final answer.
you can solve it by energy consevation.

rane · Answer

i got an answer of 2.45m ?

anonymous · Answer

add 1.5 in this and you will get your final answer.

rane · Answer

so how do we find speed at the max height ?

anonymous · Answer

speed always zero at max height.

rane · Answer

y?

anonymous · Answer

it is condition when vertical velocity of object is 0 that's the max height it achieve.