there are eight job applicants sitting in a waiting room - four women and four men. If two of the applicants are selected at random, what is the probability that both will be men?

Question

ganeshie8 · Answer

how many total ways u can choose "two" applicants from "eight" applicants ?

anonymous · Answer

28??

anonymous · Answer

16?

ganeshie8 · Answer

u can choose "two" applicants from "eight" applicants in $\large ^8C_2 =  28$ ways

anonymous · Answer

how can we calculate without using calculator??

ganeshie8 · Answer

and u can choose "two" men from a group of "four" men in $\large ^4C_2 = 6$ ways

anonymous · Answer

but i'm not allowed to use calculator

ganeshie8 · Answer

so the probability for choosing both men =  $\large \frac{6}{28} = \frac{3}{14}$

ganeshie8 · Answer

you dont need calculator

ganeshie8 · Answer

use below formula :-

$\large   ^nC_r = \frac{n!}{r!(n-r)!}$

anonymous · Answer

oh okayy ... i know this formula.. thanks alot!!

ganeshie8 · Answer

$\large   ^8C_2 = \frac{8!}{2!(8-2)!} =\frac{8!}{2!6!} = \frac{8\times 7\times 6!}{2!6!} =  \frac{8\times 7}{2} = 28$

ganeshie8 · Answer

np... u wlc :)

anonymous · Answer

i have few more probabilities question... will ya help??

ganeshie8 · Answer

sure il try :)