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Find the Integral lnx/3x
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\[\int\limits_{}^{}(lnx/3x)dx\]
by parts comes to mind
the 1/3 is a constant so your pretty much left with determining the ln(x)/x portion
So I can make it \[1/3\int\limits_{}^{}lnx/x\] Would my u be x or lnx?
hmm, u sub 1/x is the derivative of ln(x) let u = ln(x) du = dx/x, x du = dx u*x du ------ = u du x
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So xlnx/x?
no what is the integral of u du ?
\[let~u=ln(x)\] \[\frac 13\int u~du\]
\[\frac 13\int\frac 1x~ln(x)~dx\] \[u = ln(x)~:~du=dx/x\\~~~~~~~~~~~~~~~~ x~du = dx\] \[\frac 13\int\frac xx~u~du\] \[\frac 13\int u~du\]
so u^2/2, times 1/3 and we know what u is equal to
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