Question

How do I find the exact value for cot(-arcsin(1/7))?

Answer 1

you know what cot(-u) equals to?

Answer 2

would it not be the same as -cot(u)?

Answer 3

that's correct. so you have
-cot(arcsin(1/7)) yes?

Answer 4

yes

Answer 5

if you let θ = arcsin(1/7), what is the equivalent form?

Answer 6

7?

Answer 7

try again

Answer 8

sin(theta) = 1/7?

Answer 9

Im just not sure. I know cot(arcsin(x)) = sqrt{1-x^2/x}

Answer 10

well, you can use that formula or you can through the process by hand. Either way will give u the correct answer

Answer 11

it's supposed to be (sqrt(1-x^2))/x btw

Answer 12

When I use the formula I get to (sqrt(48/49))/-1/7, but get stuck right there

Answer 13

sqrt(48/49) = (sqrt(48)/7) / (-1/7) = -sqrt(48) = -4sqrt(3)

Answer 14

Which would be the exact value?

Answer 15

How would I find it by hand?

Answer 16

-4sqrt(3)

Answer 17

Yes, what is the method by hand?

Answer 18

sin(θ) = 1/7


what's cot(θ) then?

Answer 19

x/y which would give me the same answer. Where I could find x by using the Pythagorean. Awesome, much more simple than I thought. Thank you

Answer 20

yw