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An arrow is shot from a bow at 20.0 m/s at an angle of 65º above the horizontal. The arrow leaves the bow at a height of 1.80 m. At what height will it strike a wall that is 10.0 m away? (Remember to connect the two motions of the arrow using time.) y = _____ m
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It mentions the two motions. One is the horizontal direction, with no acceleration. You can break up the velocity into it's components, take the \(x\)-component, and then see how much time it takes to get to the wall. Why does that help? Well, it mentions connecting the two motions with time! So, you found the time. Notice that you can now use your vertical distance formula \(y=y_0+v_{0, y}\ t+\frac12a\ t^2\) And you have everything you need! :)
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