What type of triangle is formed by joining the points D(7, 3), E(8, 1), and F(4, -1)?
u can get it by drawing these points to there x and y coordinates
first we draw it if it obvious then we have the answer if we didnt got it yet then u would move to plan b
soo now we have to find all the length of the three lines we have DE DF and FE if we have two points and we want to have the length of the line between them we use this rule \[L=\sqrt{(X _{2}-X _{1})^{2} + (Y _{2}-Y _{1})^{2}}\]
i will do one and u do the rest i will leave the finall answers soo u can make sure lets say we need to find the length of line DE DE=\[\sqrt{(8-7)^{2} + (1-3)^{2}}= \sqrt{5}\]
and like with we get DF= 5 EF= \[2\sqrt{5}= 2.1147\]
now we define what that triangle is if the square of largest line equlas the squares of the other two lines then this triangle is right angled if it is bigger than them it is Obtuse triangle if it is smaller than them it is Acute-angled triangle
the tallest line here is Df = 5 (DF)^2= 25 and (DE)^2+(EF)^2= \[(2\sqrt{5})^{2} + (\sqrt{5}) ^{2} = 25 \]
that means we have a right angle triangle
this is another way of how to work a problem like that http://www.teacherschoice.com.au/maths_library/trigonometry/triangle_given_3_points.htm
Join our real-time social learning platform and learn together with your friends!