Mathematics
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OpenStudy (anonymous):
Change (3, 2π) into rectangular form.
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OpenStudy (anonymous):
\[x=3\cos 2\pi,y=3\sin 2\pi~ squaring ~ and~ adding,we~ get ~?\]
OpenStudy (anonymous):
well I got (3,0) as my coordinates, but idk if thats right
OpenStudy (anonymous):
\[x^2+y^2=3^2=9\]
OpenStudy (anonymous):
ok, what's next?
OpenStudy (anonymous):
(9, 1) ???
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OpenStudy (anonymous):
i have completed the solution.
OpenStudy (anonymous):
\[x^2=3^2\cos ^22\pi \]
similarly for y^2 and then add
OpenStudy (anonymous):
wait you mean, x^2+y^2=3^2=9 is the answer?
OpenStudy (anonymous):
wait I don't get it
OpenStudy (anonymous):
like for this problem Change (2, 20°) into rectangular form.
I got (1.9, 0.68)
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OpenStudy (anonymous):
was your answer correct?
OpenStudy (anonymous):
i don't know since I haven't submitted it
OpenStudy (anonymous):
how you did it ?
OpenStudy (anonymous):
you are on complex numbers or changing polar to rectangular co-ordinates.
OpenStudy (anonymous):
x=3cos 2 pi=3*-1=-3
y=3 sin 2 pi=3*0=0
rectangular coordinates are (3,0)
if you want equation in rectangular form ,that i have already given.
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OpenStudy (anonymous):
corection x=3 cos 2 pi=3*1=3
OpenStudy (anonymous):
x=2 cos 20=1.9
y=2 sin 20=0.68