Question

4. A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?

Answer 1

please vote http://www.signazon.com/contest/grad2014/lkkajqe5/

Answer 2

lol i voted can i get any help

Answer 3

@katragaddasaichandra

Answer 4

u didnt vote

Answer 5

i chcked

Answer 6

check again dude

Answer 7

i chckeed but u didnt

Answer 8

did u type the words

Answer 9

idid

Answer 10

When the ball hits the ground, its position (height) will be zero. So,

0 = -16t² + 60t + 6

Solve for t, and t ≈ 3.8475, or about 4 seconds. The answer for 3.

Answer 11

its asking what height its gonna be


A.35ft
B.40ft
C.42ft
D.45ft

Answer 12

This does not factor, so we can do either of two things. One is to use the quadratic formula: t= [-B plus/minus the sqrt(B^2-4AC)]/(2A)
In our case, A is -16, B is 60, and C=6

Using the quadratic formula, we get:

t=[-60 plus/minus the sqrt(60^2-4*(-16)*6)]/(2*-16)

t=[-60 plus/minus the sqrt(3984)]/-32

t=(-60+63.119)/-32 ~~~~ or ~~~~ t=(-60-63.119)/-32

t= -.097 ~~~~ or ~~~~ t=3.847

Since we cant have a negative time value, -.097 cannot be a solution.

Thus, the ball hits the ground at t=3.847 seconds (rounded)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...

B) To find the heigh of the ball at t=3 seconds, we sumply plug 3 into our h(t)= -16t^2+60t+6

h(3)= -16*(3^2)+60*3+6
h(3)= -16*9+180+6
h(3)= 42

At t=3 seconds, the ball is 42 feet above the ground.

Answer 13

it is c

Answer 14

please vote

Answer 15

http://www.signazon.com/contest/grad2014/lkkajqe5/