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the partial derivative 4ye^(4xy) the answer is 16xye^(4xy)+e^(4xy)(4). how do they get that answer please show work
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implicit differentiation is my guess
f(x,y)=e^(4xy) fx=4ye^(4xy) and fy=4xe^(4xy) i dont understand how they got fxy?
\[\begin{align*}\frac{\partial}{\partial y}4ye^{4xy}&=4\frac{\partial}{\partial y}[y]e^{4xy}+4y\frac{\partial}{\partial y}[e^{4xy}]\\ &=4e^{4xy}+4ye^{4xy}\cdot\frac{\partial}{\partial y}[4xy]\\ &=4e^{4xy}+4ye^{4xy}(4x)\\ &=4e^{4xy}+16xye^{4xy}\end{align*}\] In order, that would be product rule and chain rule, then simplification.
thank you
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