Question

What is the equation of the axis of symmetry for the function shown below?

y-1= -2(x+3)^2

Answer 1

axis of symmetry is x+3=0

Answer 2

so 0?

Answer 3

3?

Answer 4

no ,x+3=0,or x=-3

Answer 5

The general axis of symmetry formula for a parabola is x = -b/2a
You should first separate y from everything else:
y = -2(x+3)^2 + 1 and reach a point where you have y = ax^2 + bx + c
So for your equation:
y = -2(x^2 + 6x + 9) + 1
y = -2x^2 - 12x - 18 + 1
y = -2x^2 - 12x - 17
Then you would have a = -2, b = -12, c = -17
So the axis of symmetry:
x = -(-12)/2*(-2)
x = 12/-4
x = -3

Answer 6

Oh, or just what surjithayer said :)

Answer 7

\[-\frac{ 1 }{2 }\left( y-1 \right)=\left( x+3 \right)^2\]
it is a downward parabola,with vertex at (-3,1)
and equation of axis of symmetry is x+3=0 or x=-3
cogs is also correct but approach is different than me.