Question

the acceleration a in ft/sec^2, of a particle moving along the x-axis is given by the function A(T)=e^(2t)+t^(2)e^(r). What is the average acceleration from time t=1 to time=4?

Answer 1

we can use a calculator

Answer 2

\[A(t) = e^{2t} + t^2e^r\]Is that correct?

Answer 3

What is \(r\) in that equation?

Answer 4

Maybe it's supposed to be\[A(t) = e^{2t} + t^2e^t\]?

Answer 5

Whatever it is, you can find the average of a function over an interval by integrating the function over that interval, then dividing by the length of the interval.

Answer 6

\[\text{average }A = \frac{1}{4-1}\int_1^4 A(t)\,dt\]

Answer 7

hi umm

Answer 8

is -803.98??

Answer 9

I never heard what \(r\) is in that equation, although I suppose it doesn't matter for the purposes of telling you that I don't think -803.98 is the answer. Both terms of A(t) are going to be positive between t = 1 and t = 4, so if we integrate them, we ought to end up with a positive quantity...