Question

"What are the focus and directrix of the parabola: y = 1/12x^2" ... what is the directrix and how do i find the focus and directrix?

Answer 1

what is the standard form?

Answer 2

That was the only equation given.

Answer 3

I was referring to the general equation

Answer 4

uhmmm... I'm not sure I understand what you are asking.

Answer 5

(x-h)^2 = 4p(y-k) <-- this one

Answer 6

\[y=\frac{ 1 }{ 12 }x ^{2}\]

Answer 7

It hasn't clicked yet :/

Answer 8

try writing it as
\[12y=x^2\] which looks very much like
\[4py=x^2\] where \(p=3\)

Answer 9

since the vertex is at the origin \((0,0)\) and it opens up, the focus is 3 units up, and the directlx is 3 units below

Answer 10

Thanks a ton :)

Answer 11

you got it right? focus is \((0,3)\) and directrix is \(y=-3\)

Answer 12

Yes... took a while (very tired ugh) Thanks :)

Answer 13

yw