Calculus help on graph?
@satellite73
that is the graph of the velocity?
I think so.
if so, since velocity is the same as speed if it is positive, the largest looks to be 3 at \(t=4\)
the net distance is the area under the curve, and the total distance is the area above the curve plus the area below the curve
i guess that first part is supposed to be half a circle with radius 1, so that area is \(\frac{\pi}{2}\) the area of the triangle you get via \(\frac{1}{2}bh\)
since the base is 4 and the height is 3, the area under that large triangle is 6 the "area" under the small triangle is negative since it is below the x axis, and that is 1
therefore net change is \[\frac{\pi}{2}+6-1\] where as total distance is \[\frac{\pi}{2}+6+1\]
So the net force is 5 + pi/2 ? (thats the option given)
net force?
Opps, sorry I meant net distance lol. Im taking both physics and calculus at the same time so I typed that without thinking.
net change, yes
Thanks!
may the change be with you
unless you have any spare force
Join our real-time social learning platform and learn together with your friends!