Question

http://i57.tinypic.com/2m2j9sk.jpg

Answer 1

I thought the answer was 3/y but thats incorrect

Answer 2

i hate compound fractions

Answer 3

multiply top and bottom by \((y+3)(y-3)\) cancelling as you go

Answer 4

\[\frac{y(y+3)-y(y-3)}{y(y+3)+y(y-3)}\] is a good first step
then cancel the common factor of ](y\) top and bottom and get
\[\frac{y+3-(y-3)}{y+3+y-3}\]

Answer 5

Takes awhile!

Answer 6

http://tinypic.com/view.php?pic=2mpl79u&s=8#.UxlKiuddVFI

Answer 7

oh wait, i made a dumb mistake

Answer 8

disregard that*

Answer 9

\[\frac{y(y-3)-y(y+3)}{y(y-3)+y(y+3)}\]

Answer 10

http://i57.tinypic.com/ibhudd.jpg

Answer 11

too much work, cancel the \(y\)'s first
\[\frac{y-3-(y+3)}{y-3+y+3}\]

Answer 12

you did all that, but somehow were off by a minus sign
\[\frac{-6}{2y}=-\frac{3}{y}\]