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Prove that there is no positive integer n such that: 90 < 2^n × (n + 1) < 100
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2^7 = 128 > 100, so we're down to n = 1,2,3,4,5,6 we can check each n and show that it's false
2^6 (6 + 1) > 2^6 (2) = 2^7, show 6 doesn't work either
2^5 (5+1) = 2^5 (2 * 3) > 2^6 (3) > 2^6, so 5 doesn't work
Thanks. I didn't know where to start. Discrete math is hell.
yeah, this is one of those proofs that we can easily break up into cases.
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