The vertices of a triangle are P(-7,-4), Q(-7,-8), and R(3,-3). Name the vertices of the image reflected across the line y=x. a) P'(4,7), Q'(8,7), R'(3,-3) b) P'(4,-7), Q'(8,-7), R'(3,3) c)P'(-4,-7), Q'(-8,-7), R'(-3,3) d) P'(-4,7), Q'(-8,7), R'(-3,-3)
@johnweldon1993 , could you help w me this & a few other questions ?
Yeah if I can :) So when y = x ...this means you just switch the coordinates (-7,-4) would become (-4 , -7) So your answer would be ...?
C ? :)
Perfect :)
Do you want me to make a new post for my other questions or do you want to answer them on this post ?
Just do it here, I honestly don't care about medals lol...make it easier on yourself :)
haha okay because some people tell me to make new posts so they can get medals , so I just thought I'd ask lol but give me a minute to type the question :)
Of course :)
Find the image of O(-2,-1) after two reflections , first across the line y=-5 , and then across the line x=1. a) (-2,-1) b) (-1,-6) c) (4, -9) d) (1,-5)
So this would be C (4,-9) :)
lol , I thought it was D, I was waaaay off:p
Lol well want to know a trick?
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The vertices of a triangle are P(-2,-4), Q(2,-5), and R(-1,-8). Name the vertices of the image reflect across the y-axis. a) P'(-2,-4), Q'(2,-5), R'(-1,-8) b) P'(-2,4), Q'(2,5), R'(-1,8) c) P'(2,-4), Q'(-2,-5) , R'(1,-8) d)P'(2,4), Q(-2,5), R'(1,8)
Well the distance is 4 right...we have to go 4 down...to get from our point, to y = -5 So now we just go 4 to meet the line...but since we are reflected over it...we go 4 MORE....so we go from -1.....down to -5 .....then down to -9.... Right? That's the trick to these types of problems
Sorry I didn't see you say do you want to know a trick till I got down typing my question lol
Lol it's alright...still there in case you want to see it :)
When you flip something over the y-axis...you are making the x-values change between negative and positive...so when you flip (-2,-4) over...you then get (2 , -4) So this answer is....?
C ? :)
Deja vu lol....yes Correct :)
The vertices of a triangle are A(-6,-4), B(-3,5), and C(1,-1). Name the vertices of the image reflect across the x-axis. a)A'(-6,4), B'(-3,-5), C'(1,1) b)A' (-6,-4), B'(-3,5),C' (1,-1) c) A'(6,-4), B'(3,5) , C'(-1,-1) d)A'(6,4), B'(3,-5), C'(-1,1)
And here, when you reflect across the x-axis...you are only changing the y-values between positive and negative... so (-6,-4) would become (-6 , 4) So this one is ?
A :)
Awesome :)
Next one I want you to tell me what you think the answer is first :)
okay :)
Which graph shows a triangle and its reflection image in the x-axis I think this one is the last picture lol
And you would be correct :)
I got 100% , thank you :) I have other math problems I need help on but you don't have to help me no more if you don't want too lol
That was all you miss smarty pants :) and well it's going on 2am here, so if I start to slow down answers you'll know why :P
haha well I wouldn't have been able to figure it out without you're help:p & it's 2 am here too , i literally been on the computer since about 10am doing work -_-
lol I've been between here, my college, work, homework, and ironically back here to "relax" haha well no its easier math than what I'm currently working on though lol
haha if i think my math works hard & i only take Geometry in highschool i can only image how hard you're math is . but im about to post another question :)
Lol go ahead hun :)
which choice describes the translation represented by the translation rule (x,y) (x+4,y-1) a) 4 units to the right and 1unit down b) 1 unit to the right and 4 units down c) 4 units to the left and 1 unit up d) 4 units to the left and 1 unit down
When you go positive in the x-direction you go to the right....when you go negative in the y-direction you go down...so this is...?
A ? :p
See you don't need me you are a master :D
haha no i do need you , the only reason im getting it is because you're explaining how to get the answer.
Lol well I'm glad you're understanding :))
Use a translation rule to describe the translation that is 10 units to the left and 3 units down \[a) (x,y) \rightarrow (x+10, y+3) \] \[b) (x,y) \rightarrow (x-10, y+3)\] \[c) (x,y) \rightarrow (x-10,y-3)\] \[d) (x,y) \rightarrow (x+10,y-3)\]
you tell me :)
C , maybe lol
\[ \checkmark\] :)
Ehh you weren't so sure so lets make you sure! \[\huge \color{red} \checkmark\] Lol :)
But no.....when you go to the left...you subtract from the 'x' When you go to the right you add to the 'x' When you go up, you add to the 'y' and when you go down, you subtract from the 'y' :)
omg im so confused lol
With what? you have the right answer 'C' lol
I just listed what the rules are Translation to the left = x - something Translation to the right = x + something Translation up = y + something Translation down = y - something
oh haha you said "but no" so I thought I got in wrong , so that's why I was confused because I thought it was right .
Lol ohhh yeah that was a bad choice of words to being a post lol...sorry :P
its okay haha :)
Alright think you have a pretty good understanding now hun?
yeah I think so , the next question is basically the same as the last one I just posted so I don't really feel like typing it again but it says 9 units to the right and 9 units down , so to the right is positive and down is negative right so would the answer be \[(x,y) \rightarrow (x+9,y-9) \]
Perfect :)
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