Find the y value for point L such that JL and KL form a 3:1 ratio.
2.5
-1
-0.5
2
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OpenStudy (anonymous):
Parth (parthkohli):
Do you know about similar triangles?
Parth (parthkohli):
|dw:1394179532929:dw|
Parth (parthkohli):
First things first: use the distance formula to find the distance between J and K. That'd give you the length of JK.
OpenStudy (anonymous):
i got \[\sqrt{5}\]
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OpenStudy (anonymous):
and then i found the square root = 2.2
OpenStudy (anonymous):
@ParthKohli
OpenStudy (anonymous):
how did you get \[\sqrt{5}\]
OpenStudy (anonymous):
(4-4)^2 + (-2+4)^2
1+4
5
Parth (parthkohli):
Eh?
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OpenStudy (anonymous):
ill draw it up for you
OpenStudy (anonymous):
i used the distributive prop.
Parth (parthkohli):
@jeremyggg Could you take the charge? I'm currently busy doing other things at the moment. Thanks.
OpenStudy (anonymous):
i got the answer thanks guys!
OpenStudy (anonymous):
-0.5
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OpenStudy (anonymous):
ahaha! ok! my drawing would have worked but it wasn't pretty! did you figure out why it wasn't \[\sqrt{5}\]
OpenStudy (anonymous):
lol yess i crossed multiplied 3/4 x 6/1 = 18/4 = 4.5
4 - 4.5 = -0.5
OpenStudy (anonymous):
heheh that is the simple way! but your way of getting the length of the line wasn't right. you would make a right triangle and then see how long each side was, then do pythag of a^2+b^2 = c^2! good job though!