Question

What are the values that satisfy the trigonometric equation for 0 < q < 2?

\[\sin \theta + \tan( -\theta) = 0\]

Answer 1

Use the fact that \(\tan(-\theta) = \tan(\theta)\). You have the following equation:\[\sin(\theta) - \tan(\theta) = 0 \Rightarrow \sin\theta = \tan\theta\]Does that make sense?

Answer 2

Not really... I barely have any foundation in Trig whatsoever.
I'm not sure how to plug anything in..

Answer 3

OK, let me explain. Also, I did a typo there: \(\tan(-\theta) = -\tan(\theta) \).

Answer 4

First, do you understand the following relation?\[\tan\theta = \dfrac{\sin \theta}{\cos \theta}\]

Answer 5

To some extent... A friend walked me through this type of problem before.

Answer 6

OK. You only need to know that. Also, do you know any trig identities?

Answer 7

like beta and alpha?

Answer 8

Trigonometric identities are some things that are true for all angles. For example, the following...\[\dfrac{\sin\theta}{\cos\theta} = \tan\theta \]...will be true for any \(\theta\) you can imagine. Ever.

Answer 9

There's other theta's? o.o

Answer 10

\(\theta \) is any angle.

Answer 11

I'm just saying that an identity is any relation that is true for all angles.

Answer 12

Oh... got it.