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Mathematics 15 Online
OpenStudy (anonymous):

Simplify the expression

OpenStudy (anonymous):

\[\frac{ \sqrt{-4} }{ (5 + 2i) - (3 - 4i) }\]

Parth (parthkohli):

Do you know what the numerator is, in terms of \(i\)?

OpenStudy (anonymous):

2i?

OpenStudy (anonymous):

3\10 + i 1\10

Parth (parthkohli):

That's right. How about the denominator? What would you do to simplify it?

OpenStudy (anonymous):

distributive property?

OpenStudy (anonymous):

5 + 2i - 3 + 4i?

OpenStudy (anonymous):

2 + 6i?

Parth (parthkohli):

Yes, kudos!

OpenStudy (anonymous):

yaay!!

OpenStudy (anonymous):

then how do you go from here?

Parth (parthkohli):

The numerator is \(2i\) and the denominator is \(2 + 6i \). Can you factor the denominator?

Parth (parthkohli):

It will help us do some cancellations.

OpenStudy (anonymous):

i give the answer [\frac{ 3 }{ 10 } + \frac{ i }{ 10 }]

OpenStudy (anonymous):

factor in what way?

Parth (parthkohli):

Like \(2 + 6i = 2(1 + 3i)\)

OpenStudy (anonymous):

oohhh....okay...now what?

Parth (parthkohli):

The numerator is \(\color{blue}2i\) and the denominator is \(\color{blue}2(1+3i)\). That bit of color will give a hint to you!

OpenStudy (anonymous):

so those two cancel each other out!

Parth (parthkohli):

Yeah, the 2s do, at least!

OpenStudy (anonymous):

so whats the answer?

Parth (parthkohli):

We're soon gonna find it. Right now, we have\[\dfrac{i}{i + 3i}\]

OpenStudy (anonymous):

can the i's cancel out?

Parth (parthkohli):

Not really, no.

OpenStudy (anonymous):

oh wait a minute...these are the answers given on my assignment.... a. the quantity of three plus I all over ten b. the quantity of three minus I all over ten c. the quantity of three plus I all over eight d. the quantity of three minus I all over eight

Parth (parthkohli):

So your assignment hates when you put that \(i\) in the denominator. Do you know of a way to remove it from the denominator and get it to the numerator?

OpenStudy (anonymous):

idk

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