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Chemistry 24 Online
OpenStudy (anonymous):

Anyone can explain this question? When the concentration of A is doubled, the rate for the reaction: 2 A + B-->2 C quadruples. When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with the experimental observations? The answer is: Step 1: 2A-->D (slow) Step 2: B + D --> E (fast) Step 3: E --> 2C (fast)

OpenStudy (abb0t):

The answer is what?

OpenStudy (anonymous):

Here The answer is: Step 1: 2A-->D (slow) Step 2: B + D --> E (fast) Step 3: E --> 2C (fast)

OpenStudy (anonymous):

But I don't understand the theory for mechanism. If anyone can explain, that would be great.

OpenStudy (abb0t):

Well, first step is rate determining step.

OpenStudy (anonymous):

if thats not the formula you need the formula first

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