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OpenStudy (anonymous):
How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?
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OpenStudy (stmoney):
3.80 mol x ( 6.022x10^23 molecules)/(1 mol)
OpenStudy (joannablackwelder):
That will calculate molecules of copper(II) phosphate. You also need to covert from molecules to atoms of phosphorous using the conversion 2 atoms of phosphorous in each molecule. Let me know if you don't understand how I came up with that conversion.
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