Help on trig! Fan & medal
Find the exact value for tan(195 degrees)
is it 2-√3 ?
tan 195 can be written as tan (180 + 15) Rule: tan (180 + 'anything') = tan ('anything') So tan(180 + 15) = tan 15
Yes, i think it is. I have done this quite a number of times to be honest. O.O
No it has to be in radians
Oh okay how do i mke sure ?
Radians or degrees, the value will always be the same. :) Is it tan (195 radians) ??? [Then it'd be different]
not its degrees but the answer has to be in radians
use the Unit Circle :)
yes 2-√3
Yes, it is \(2 - \sqrt{3}\) The answer will be a ratio and will not be an angle [Like in radians or degrees]
keeping in mind that \(\bf tan(\theta)=\cfrac{y}{x}\)
Oh okay well thanks guys :)
:)
What about when it says for example find exact value for sin(π/3 - π/4) how do i do this :o
Do i just subtract and then find sin orrrr?
Do you know what sin(A+B) expands to? :D
mmm no :/
To find the value in terms of irrational numbers, you need to know the property. sin(A+B) = sinA.cosB + sinB.cosA :)
Hmm okay soo how would sin(π/3 - π/4) look like?
Take A = pi/3 , B = pi/4 And then try using the identity! ^^ pi/3 and pi/4 are in radians, convert them to angles in degrees to make the calculation much simpler. :)
Soooo.. (sin π/3* cos π/4 + sin π/4* cos π/3) ? :)
Yes! :D
awesome :) now i just put it in my calculator?
if it in radian = 0.224938 cause 1^r = 57.29578 degree
YES, you may use the calculator. :) [We are not allowed to in our school]
it says find the exact value so doesnt that mean in radians tho? so can i use a calculator?
If you use a calculator you'll get decimal values which are pretty exact. :P But if you do know the basic trigonometric equation values, you may use that. pi/3 = 60 pi/4 = 45 So sin π/3 * cos π/4 + sin π/4 * cos π/3 = sin 60 * cos 45 + sin 45 * cos 60\[=\frac{\sqrt{3}* 1}{2* \sqrt{2}} + \frac{1* 1}{2* \sqrt{2}}\] \[= \frac{\sqrt{3} + 1}{2*\sqrt{2}}\] sqrt{2} = 1.414 sqrt{3} = 1.732 now you can calculate with a calculator. :)
wait where did you get this 3√∗12∗2√+1∗12∗2√ haha?
Those are the basic trigonometric values. I remember them. :P I am in grade 11, we sort of have to remember them, where I study. :D
Oh nvm i get it
Yes lol :p
yeah same im just bad at remembering those i have a table :p
They are not that difficult if you find a relation. Like sin 30' = cos 60' = 1/2 and sin 60' = cos 30' = √3/2 and sin 45 = cos 45' = 1/√2 And so on and so forth. :D
Actually I do agree with you, it can be found out using a calculator, but sometimes it is better to remember the basic values. :)
Yeah haha :) so it would be 1.414 + 1/2 * 1.732 = 2.6?
It'll be 2.732/2.828 because √3 + 1 = 2.732 and 2*√2 = 2.828
0.96605 :)
Ohhh so you can round it up and the answer would be just 1 ?? :)
Yes, you may, but then I think they need the exact value. :)
oh yeah thats right :p my teacher told me that the exact value meant in radians sooo it would be 0.96605 radians?
No no no.. if x = sin y then y is the angle and it may be in radians or degrees and x is just the value. I can teach you a bit of trigonometry if you want. :)
Haha please :) i am so confused lol i have my final to take soon
Sure. So which grade are you in? And what are you learning in trigo now?
Im in 11th. Almost done with trig. I have an A and i've understood everything except a few things in the most recent lessons
Like identities
Like i dont get what verified trig identities are
Oh cool same as me. :D Okay, so trigonometry is just ratios actually nothing tough with that. The simplest way to understand that is by using a right angles triangle. |dw:1394231153875:dw| Here, a may be in radians or in degrees. So sin(a) = some value. a is in degrees or radians and 'some value' is just a ratio with no units absolutely. :)
Yeah that makes sense :)
Great. You should try some yourself, and if you have a doubt just hit me up. :)
Okay thanks :)))) you are really a big help :) i'm going to do that problem over with subtraction. Do you mind checking it when im done?
Not at all. :)
Okay thanks :) so i dont use this formula anymore sin(A+B)
No, but it is similar. sin(A+B) = sinA.cosB + sinB.cosA sin(A-B) = sinA.cosB - sinB.cosA cos(A+B) = cosA.cosB - sinA.sinB cos(A-B) = cosA.cosB + sinA.sinB It may take some time, but it is helpful to remember these! ^
ok so we use sin(a - b)
tan(A+B) = \[\frac{tanA+tanB}{1-tanA.tanB}\] tan(A-B) = \[\frac{tanA-tanB}{1+tanA.tanB}\]
Yes, and we do that, because it asks you in your question. sin(pi/3 - pi/4)
wait why that one hahah that looks confusing :/
Oh okay good haha :p sooo
sin(A-B) = sinA*cosB + sinB*cosA (sin pi/3* cos pi/4 - sin pi/4* cos pi/3) sin 60 * cos 45 - sin 45 * cos 60 √3 * 1/2*√2 - 1 * 1/2*√2 =
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