Question

Differentiate implicitly:

Answer 1

\[\LARGE tan(x-y)=\frac{y}{(4+x^2)}\]

Answer 2

for a person at 99 i think you can help yourself XD jk jk

Answer 3

the tan(x-y) is throwing me off

Answer 4

and you already know how to do this, so stop asking dumb questions -_-

Answer 5

So it turns to..
\[\LARGE \frac{tanx-tany}{1+tanxtany}=\frac{y}{4+x^2}\]
So quotient rule on both sides? >.<

Answer 6

No quotient on the left :o
Just derivative of tan, then chain rule.

Answer 7

Hmm, you sure we don't use the trig add/sub formulas here? @zepdrix

Answer 8

I'm not sure why you would want to do that :o
Makes a lot more work for you.

Answer 9

Hmm, okay you're right xD
\[\LARGE sec^2(x+y)*1+y'=\frac{(4+x^2)(y')-(2x)(y)}{(4+x^2)^2}\]?

Answer 10

Woops, dont' forget the brackets on the chain rule!\[\Large\bf\sf \frac{d}{dx}\tan(x-y)\quad=\quad \sec^2(x-y)\cdot(1-y')\]

Answer 11

Right! Question being how do we isolate y' now? xD

Answer 12

Crap my LoL game is starting +_+ gotta go!!

Answer 13

Okay T_T

Answer 14

@whpalmer4 ? >.<

Answer 15

OMG HE PLAYS LEAGUE

Answer 16

yeaaaaaaaaaaaaaaaaaaaaaaaaaa

Answer 17

Sham I have you blocked on LoL :>

Answer 18

i have you blocked on here, and u dont have LoL, and you don't block ppl on LoL either you just put on ignore list.
noob

Answer 19

There is a way ;) beyond ignore list *points* I do, barely enough to consider myself one though :/

Answer 20

Figure this out Luigi? c: