Question

If 125 cal of heat is applied to a 60.0-g piece of copper at 24.0∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C)

Answer 1

Heat=mass* specific heat* change in temp

Answer 2

125 cal = 60 g * 0.0920 cal/(g C) * (T-24C)
Solve for T.
Note: change in temp is always final-initial