Two pulleys, one with radius 2 in. and the other with radius 8 in., are connected by a belt. If the 2 in. pulley is caused to rotate at 3 revolutions per min. determine the revolutions per min of the 8 in. pulley.

Question

anonymous · Answer

I think this would be the equation..

c = 2 pi r

a = 2 pi 2
a = 12.566371

b = 2 pi 8
b = 50.265482

revb/reva = (a/b)
revb = reva(a/b)

anonymous · Answer

2*pi*2*3 = 2*pi*8*x........... Solve for x.

artemisxrpg · Answer

Can you explain a little better?

anonymous · Answer

The rope goes the same speed wherever it is.
On the first pulley that is 
2 pi (2) (3/minute) = 
2 pi (8) (x/minute) for the second pulley

x = (2)(3)/8 = 6/8 = 3/4

artemisxrpg · Answer

Why do you multiply the 1st and 2nd pulley by 2pi?

artemisxrpg · Answer

or is that suppose to be the circumferences times the rev/min?