lnx-5x=0 find x
is it like ln(x-5x)=0 or .....
hello tell me to understand
Go to wolframalpha.com and ask the question.
Mom! There's evil in my closet! EVIIIILLL!!!
any way x=\[e^{5x}\]
you have one variable but in two side with exponential so wolframalpha.com canot solve it hhhhhhh
the solution is no solution
no...
you cant say x(1-5) cause the x with ln and -5x is alone so you can't say like ln x-5x=0 ln x(1-5) = 0 ln -4x= 0 -4x = e^0 -4x = 1 x = -1/4
lnx = 5x
so x = e^(5x) it don't have any solution
when we say x = e^(5x) so we need x= number that make the two sides be equal there is no any number to this
until if we derive it be 1=5e^(5x)is critical point so .........
That is not the right equation. Please think about the Domain. \(f(x) = \ln(x) - 5x\) Domain \(x > 0\) \(g(x) = e^{5x} - x\) Domain \(x \in \mathbb{R}\) Neither has a solution, f(x) = 0 or g(x) = 0.
but how much ln (0) =
\(\ln(0)\) is not a number.
Join our real-time social learning platform and learn together with your friends!