Which represents the compound inequality x < -2 or x ≥ 3 using interval notation? A. x e(-∞,-2) U [3,∞) B. x e(-∞,-2) n[3,∞) c. x e(-2,3] d.x e(-∞,-2] Need help i dont understand this one at all.
x< -2 so x can go from -infinity to -2 \[also , x \ge 3 , \] so x can go from \[[ 3 , \infty)\]
so just put union U in the centre as both can be the results
tell me the answer :)
Which is the solution set of the compound inequality? -4 < a + 2 < 10 http://prntscr.com/2yxwyj <--- list of answers need help on one more after this if you can.
no problemo
okay , so , first -4 < a + 2 subtract 2 from both sides -4 -2 < a +2 -2 -6 < a then the second one a + 2 < 10 solve similarly and tell me what u get
so i subtract 2 from both sides?
yep , the aim is to get 'a' alone on one side
so then its a<10
no , from both sides , remember ?
u cant subtract just on one side
so then its a<8
exactly
now put union U
use what i taught you , and tell me what u get
ill check it
B?
B. x e(-∞,-2) n[3,∞)
ya
okay
@hazem-wardat , dont just give the answer , we have to help them understand it
okay thank you
its no use if they dont master it on their own , u wont be there during the exam
ur welcomr :D
for which one?
ok am sorry but B. x e(-∞,-2) n[3,∞) is the right answer
ur third answer is B , as u rightly chose
@Ang3lEyez96 Hey! If somebody helps you, it is good to give them a Kudos! :D
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