Question

Which of the following statements have the same results?:

I: f(1) when f(x)=5x+1
II: f^-1(3) when f(x)=2x+3/5
III: 3y-7=y+5

Answer 1

substitute each value in x
for example= f(1)= 5(1)+1= 6

Answer 2

Is the second one \(2x + \dfrac{3}{5}\), as you have written it, or did you intend \(\dfrac{2x+3}{5}\)?

Answer 3

For the first one I got 6. But I’m not sure with the others…
This is the second one:

Answer 4

Do you see how that is NOT what you originally wrote?

Answer 5

Sorry, it's what I meant to write.

Answer 6

You didn't answer my question. It is important to know how and why it is different.

f(1) when f(x)=5x+1 ==> 5(1) + 1 = 5 + 1 = 6 -- We've seen that, already.

Answer 7

3y - 7 = y + 5

Subtract y

2y - 7 = 5

Add 7

2y = 12

Divide by 2

y = 6

Answer 8

The parentheses I added are NOT optional. Remember your Order of Operations.

f^-1(3) when f(x)=(2x+3)/5

3 = (2x+3)/5

Multiply by 5

15 = 2x + 3

Subtract 3

12 = 2x

Divide by 2

6 = x

They all seem to be coming out 6.

Answer 9

I see the difference now, I'll keep that in mind.
Thanks for your help:)