Carbon disulfide and chlorine react according to the following equation:

CS2 (g) + 3 Cl2 (g) → S2Cl2 (g) + CCl4 (g)

When 1.00 mol of carbon disulfide and 3.00 mol of chlorine are placed in a 2.00 L container and allowed to come to equilibrium, the mixture is found to contain 0.250 mol of carbon tetrachloride. What is the amount of chlorine at equilibrium? Report your answer in number of moles to 2 s.f. Do not include units in your answer. Do not use scientific notation for your answer.

Question

Carbon disulfide and chlorine react according to the following equation:

CS2 (g) + 3 Cl2 (g) → S2Cl2 (g) + CCl4 (g)

When 1.00 mol of carbon disulfide and 3.00 mol of chlorine are placed in a 2.00 L container and allowed to come to equilibrium, the mixture is found to contain 0.250 mol of carbon tetrachloride. What is the amount of chlorine at equilibrium? Report your answer in number of moles to 2 s.f. Do not include units in your answer. Do not use scientific notation for your answer.

anonymous · Answer

use ice box

anonymous · Answer

|dw:1394306861303:dw|
I think it's suppose to look something like that

anonymous · Answer

Is that suppose to have a 2 headed arrow or just 1??

anonymous · Answer

By the looks of it, anyhow, x is = 0.125M, unless I did my math wrong. So then just put P(products)/P(reactants) now that you know what x is, find the Kg of it... or not?

anonymous · Answer

the arrow is two headed....but that seems right, i was stuck on the s2cl2 and why it didnt have any info on it...thanks soo much!!! : )

anonymous · Answer

So what did you do to find the amount of chlorine? You got all the pressure at equilibrium, what was the next step that you took?

anonymous · Answer

i didnt do anything, but i assume that you plug back in the x, then find kc

anonymous · Answer

Well...  remember that this is an ICE box for gas... IDK what to do.