MINIMUM AND MAXIMUM remind me how to find the min and max?!? y=-5cos(x+3)-1
where do you think the middle line is?
the maximum of cosine is 1 the maximum of 5 times cosine is therefore 5 and so the minimum of - 5 times cosine is -1 therefore, the minimum of \(-5\cos(x)-1\) is ...
oops, i meant to say " the minimum of -5 times cosine is -5"
im looking at a graph of it and that's a very good explanation im just very lost it looks like the maximum is 4
hope it is clear that the \(x+1\) in the input has no effect on the max or min
yes, the max is 4 lets walk through it
the minimum value of cosine is \(-1\) the minimum value of 5 times cosine is therefore \(-5\) and so the maximum value of \(-5\) times cosine is 5
it looks like the minimum vale is -6 though
since you are subtracting 1 at the end, the maximum value of \(-5\cos(x+1)-1\) is \(4\)
yes, \(-6\) same reasoning as above
oh okay that makes sense
the minimum value of \(-5\cos(x+1)\) is \(-5\) and since you subtract 1 at the end, then the minimum value of \(-5\cos(x+1)-1\) is \(-5-1=-6\)
thank you thank you
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