Question

what is the midpoint of the line segment whose endpoints are (-8,12) and (-13, -2)?

Answer 1

\(\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -8}}\quad ,&{\color{blue}{ 12}})\quad &({\color{red}{ -13}}\quad ,&{\color{blue}{ -2}})
\end{array}\qquad
\left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\)

Answer 2

same as before
take the average in each coordinate
i.e. add and divide by two

Answer 3

the answers I have are

a.(-10.5, 5)
b. ((-10.5, 7)
c.(-2.5, 7)

Answer 4

so.. what did you get then?

Answer 5

c I think Im not good at this

Answer 6

\(\bf \bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -8}}\quad ,&{\color{blue}{ 12}})\quad &({\color{red}{ -13}}\quad ,&{\color{blue}{ -2}})
\end{array}\qquad
\left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)
\\ \quad \\
\left(\cfrac{{\color{red}{ -13}} + {\color{red}{ -8}}}{2}\quad ,\quad \cfrac{{\color{blue}{ -2}} + {\color{blue}{ 12}}}{2} \right)\implies \left(\cfrac{-13-8}{2}\quad ,\quad \cfrac{-2+12}{2}\right)\)

what do you think?

Answer 7

B

Answer 8

hmmm so... what would you get from the fractions?

Answer 9

what's say -13 -18 = ?

what about -2 + 12 = ?