Question

Attachment

Answer 1

graphing sucks for doing this
best bet is to add the two equations and get \[9x=18\] telling you that \(x=2\)

Answer 2

so y=-1?

Answer 3

lets check

Answer 4

yeah -1

Answer 5

\[5x+y=9\\
5\times 2+y=9\\
10+y=9\\y=-1\] looks good to me

Answer 6

So how do I graph this

Answer 7

do you have to?

Answer 8

I do

Answer 9

But if I only have one point (2,-1) I don't understand how I would

Answer 10

the first can be rewritten as \(y=-5x+9\) slope \(-5\) and \(y\) intercept \(9\)
plot a couple points

Answer 11

So could I do (2,-1) down 5 over 1?

Answer 12

the second can be written as \(y=4x-9\) slope \(4\) and \(y\) intercept \(-9\)

Answer 13

you could do that, yes

Answer 14

Would I still need to do a 2nd line?

Answer 15

yes you need two

Answer 16

lets get two points on the first line \(y=-5x+9\)

Answer 17

one is \((0,9)\) the \(y\) intercept
another is \((2,-1)\)
that should be sufficient

Answer 18

how (0,9)

Answer 19

looks good to me

Answer 20

intersection!

Answer 21

so that'll work if I do both as (2,-1) and just change the slope?

Answer 22

you see you have \((0,9)\) on the graph of one of the lines \(y=-5x+9\)
that is the \(y\) intercept, where the line crosses the \(y\) axis
because if \(x=0\) then \(y=-5\times 0+9=9\)

Answer 23

the solution is the point of intersection of the two lines

Answer 24

@vshiroky your graph is correct

Answer 25

Thank you :)

Answer 26

you don't need to plot the points i said, you can plot any two points
so going over one up five will do it
for the other, over one down 4
works fine either way
yw

Answer 27

ok i said that wrong
but you have it correct in any case