Question

Jason wants to walk the shortest distance to get from the parking lot to the beach.

a. How far is the spot on the beach from the parking lot?

b. How far will he have to walk from the parking lot to get to the refreshment stand?

Answer 1

http://www.mathwarehouse.com/geometry/similar/triangles/geometric-mean.php <---
check the SIMILAR triangles, and do the same as you did in the previous with similar figures

Answer 2

So would the equation be
\[\frac{ 18 }{ x } = \frac{ x }{ 32 }\]

Answer 3

and then would I cross multiply \[x^{2} = 576\]

Answer 4

so \[x = 24\]

Answer 5

How would I answer a and b?

Answer 6

x = 24, yes

well you found "x" so look at the picture, x = "distance from parking to beach"
y = " distance from parking to refreshments"

Answer 7

So a is 24m?

Answer 8

"x" is 24m, yes

Answer 9

Would b. be\[24 + 32 = 56 \] then?

Answer 10

wait no

Answer 11

How would I find y?

Answer 12

look at the medium-size and largest-size triangles, one could say that \(\bf \cfrac{y}{32+18}=\cfrac{32}{{\color{blue}{ x}}}\implies \cfrac{y}{32+18}=\cfrac{32}{{\color{blue}{ 24}}}\)

Answer 13

hmmm wait

Answer 14

I mixed up a few things there darn hehehh \(\bf \cfrac{y}{32+18}=\cfrac{32}{y}\implies \cfrac{y}{32+18}=\cfrac{32}{y}\)

Answer 15

though I must say, both will work :)

Answer 16

anyhow, I intended to use the middle and longest one =)

Answer 17

\[\frac{ 50 }{ y }=\frac{ y }{ 32 }\]
Then I would cross multiply
\[y^{2} = 1600\]
\[y = \sqrt{1600}\]
\[y = 40\]

Would that work?

Answer 18

Would that work? \(\large \checkmark\)

Answer 19

:D yay thank you

Answer 20

yw