A tunnel links three buildings at 2 Zinc. On rainy days, Dara uses the tunnel to go from building A to building B. On sunny days he uses the path. Dara walks between the buildings 8 times a day. How much more does he walk on a rainy day than on a sunny day?
|dw:1394321122025:dw|
Answers are: 1280ft \[8\sqrt{13600}\] \[8(160-\sqrt{13600}\] \[8(190-\sqrt{13600}\] not enough information
Find AB using the pythagorean theorem. is 8AB greater or less than 8(100+60)?
ok and after the pythagorean theorem?
Well, first find the length of AB.|dw:1394322319174:dw|
116.62
Then what?
I got that as well. then we have to measure out the lengths he walks. Our information is as follows: *He uses the path 8 times a day. *On rainy days he uses AB *on sunny days he uses 60+100
so it would be 8(166.62)(60/100)
I'm not sure where that came from. We have: 8(rainy) - 8(sunny) [or 8(sunny) - 8(rainy) if sunny is the larger one]
This still does not help me understand or solve the equation
The sunny path is 160 units long, right? That means if he uses the path 8 times, he walks 160*8 units on a sunny day
meanwhile, on a rainy day, he walks 8*116.619... units
oh wait we don't need an actual number
well the difference between the two paths is:\[\huge 160-\sqrt{13600}\] do you see why?
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