Find all rational roots for P(x)=0 P(x)=3x^3+x^2-8x-12
??
Try the Brio-Ruffini Method.
what is that?
Is the same of Synthetic method.
Can you demonstrate?
Wait
well try the rational root theorem find the factors or -12 call them p and the factors of 3 call them q then the rational roots will be p/q so \[p = \pm 1, \pm 2, \pm3, \pm4, \pm6, \pm12\] and \[q = \pm1, \pm 3\]
I'd start with 2, -2, 3, and -3 so if P(2) = 0 x = 2 is a rational root
Woah you lost me
What is p=/pm etc
ok, the rational root theorem is used to get an idea of what numbers could be the roots of a polynomial... so you have you find the possible by finding the factors of the constant term... -12 and the factors of the coefficient of the leading term 3
omg im so sorry my internet connection is so bad it translated your comment into something completely irrelevant.
well for example -1 *-3 = 3 so -1 and -3 can be factors of 3 as well as 1 * 3 = 3 but as a guess I'd try f(2)
No, yes, I understand, continue. So sorry
ok... so you are looking at 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12 as possible solutions... as well as 1/3 -1/3 2/3, -2/3, 4/3, -4/3 when you get a rational root, you can do some synthetic division or polynomial division to find the quadratic factor
another method is to just graph the curve... find the points where it cuts the x-axis
Couldn't find a root for this one P(x)=2x^4-x^3-14x+7
lol... for this one, I'd graph it... there isn't anything obvious... there is a root between 0 and 1 so try 1/2
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