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Mathematics 15 Online
OpenStudy (anonymous):

Find all rational roots for P(x)=0 P(x)=3x^3+x^2-8x-12

OpenStudy (anonymous):

??

OpenStudy (anonymous):

Try the Brio-Ruffini Method.

OpenStudy (anonymous):

what is that?

OpenStudy (anonymous):

Is the same of Synthetic method.

OpenStudy (anonymous):

Can you demonstrate?

OpenStudy (anonymous):

Wait

OpenStudy (campbell_st):

well try the rational root theorem find the factors or -12 call them p and the factors of 3 call them q then the rational roots will be p/q so \[p = \pm 1, \pm 2, \pm3, \pm4, \pm6, \pm12\] and \[q = \pm1, \pm 3\]

OpenStudy (campbell_st):

I'd start with 2, -2, 3, and -3 so if P(2) = 0 x = 2 is a rational root

OpenStudy (anonymous):

Woah you lost me

OpenStudy (anonymous):

What is p=/pm etc

OpenStudy (campbell_st):

ok, the rational root theorem is used to get an idea of what numbers could be the roots of a polynomial... so you have you find the possible by finding the factors of the constant term... -12 and the factors of the coefficient of the leading term 3

OpenStudy (anonymous):

omg im so sorry my internet connection is so bad it translated your comment into something completely irrelevant.

OpenStudy (campbell_st):

well for example -1 *-3 = 3 so -1 and -3 can be factors of 3 as well as 1 * 3 = 3 but as a guess I'd try f(2)

OpenStudy (anonymous):

No, yes, I understand, continue. So sorry

OpenStudy (campbell_st):

ok... so you are looking at 1, -1, 2, -2, 3, -3, 4, -4, 6, -6, 12, -12 as possible solutions... as well as 1/3 -1/3 2/3, -2/3, 4/3, -4/3 when you get a rational root, you can do some synthetic division or polynomial division to find the quadratic factor

OpenStudy (campbell_st):

another method is to just graph the curve... find the points where it cuts the x-axis

OpenStudy (anonymous):

Couldn't find a root for this one P(x)=2x^4-x^3-14x+7

OpenStudy (campbell_st):

lol... for this one, I'd graph it... there isn't anything obvious... there is a root between 0 and 1 so try 1/2

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