Question

I wanna know if my thoughts are correct, let's say a basketball player will do 5 throws, he can score or miss. if I wanna know the probability of 3 good throws, it seems I can use combination or permutation with repetition, I'm getting the same result, is that a coincidence?

Answer 1

@kropot72 what do you think?

Answer 2

I think that it is necessary to know the probability of the player scoring from a single throw, based on the player's stats over a large number of throws.
In that case, assuming the players history gives a 0.8 probability of a score from a single throw, the binomial distribution gives the probability of scoring on exactly three out of 5 throws as:
\[5C3\times0.8^{3} \times0.2^{2}=0.2048\]

Answer 3

ok, that helps, thank you

Answer 4

You're welcome :)