Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0, -7).
Which way does the parabola opens?
Down?
the focus should help reveal how the parabola opens
good, so which general equation are you going to use?
y=a(x-h)^+k
you could, but it doesn't have a focus embedded in that equation. The better one is (x - h)^2 = 4p (y-k). Look familiar?
Oh is the answer y = -1/28x2
well, we'll see. Do you know what (h,k) and p stand for?
(H,k) is the vertex, nd p idk
p is the distance form the vertex to the focus. So what is that distance?
-7
technically it's 7. But because the parabola opens down, we know there will be a negative sign in front. So if you plug everything the general equation above, what do you get?
I got -1/28x2
how did you get that?
I just plugged in everything
ok, so you did (x - 0)^2 = -4(7)(y-0) right?
which then gave you y = -x^2/27 ?
28*
good
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